![SOLVED:Laplace Transform of Derivatives L{y} = s L{y} - y(0) L{y} = s Y-y(0) L{y"} = s2Y sy(0) -y(0) E{y6)} = s" Lly} s"-1y(0)-sn-2y' (0) y(n-1) (0) Laplace Transform of Integral E{J; SOLVED:Laplace Transform of Derivatives L{y} = s L{y} - y(0) L{y} = s Y-y(0) L{y"} = s2Y sy(0) -y(0) E{y6)} = s" Lly} s"-1y(0)-sn-2y' (0) y(n-1) (0) Laplace Transform of Integral E{J;](https://cdn.numerade.com/ask_images/b999c46408a64b36af5801c2acbc603c.jpg)
SOLVED:Laplace Transform of Derivatives L{y} = s L{y} - y(0) L{y} = s Y-y(0) L{y"} = s2Y sy(0) -y(0) E{y6)} = s" Lly} s"-1y(0)-sn-2y' (0) y(n-1) (0) Laplace Transform of Integral E{J;
![Electrical Engineering: Ch 16: Laplace Transform (23 of 58) Laplace Transf of the 3rd Derivative - YouTube Electrical Engineering: Ch 16: Laplace Transform (23 of 58) Laplace Transf of the 3rd Derivative - YouTube](https://i.ytimg.com/vi/hxGu_Yz_OUY/hqdefault.jpg)
Electrical Engineering: Ch 16: Laplace Transform (23 of 58) Laplace Transf of the 3rd Derivative - YouTube
![Electrical Engineering: Ch 16: Laplace Transform (21 of 58) Laplace Transf of the 1st Derivative: 1 - YouTube Electrical Engineering: Ch 16: Laplace Transform (21 of 58) Laplace Transf of the 1st Derivative: 1 - YouTube](https://i.ytimg.com/vi/lLxJgCampBc/hqdefault.jpg)